difsqr difference of squares

BinaryOperator

difsqr(a, b)

a difsqr: b

a.difsqr(b)

Return the value of  (a*a) - (b*b). This is more efficient than using

separate unit generators for each operation.

{ (FSinOsc.ar(800) difsqr: FSinOsc.ar(XLine.kr(200,500,5))) * 0.125 }.play;

same as :

(

{

var a, b;

a = FSinOsc.ar(800);

b = FSinOsc.ar(XLine.kr(200,500,5));

((a * a) - (b * b)) * 0.125

}.play)